The grade of iron in an ore body containing 80 wt% hematite and 20 wt% gangue is ………………. % (upto 2 decimal places) ( At wt of Fe = 55.85, O = 16)
% of Fe in hematite (Fe2O3) = 55.85*2 / (55.85*2 + 16*3)
= 111.7/159.7 = 69.9 %
% of Fe in ore body = 69.9 % of total Hematite
= (69.9/100)*80
= 55.92 %Aans.
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